What is the critical x/(x^2+14x+48) ?

The critical x/(x^2+14x+48) is x=-4sqrt(3),x=4sqrt(3)

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critical x/(x^2+14x+48)

critical points

\frac{x}{x ^{2} + 14 x + 48}

x = - 43, x = 43

Solution steps

\frac{x}{x ^{2} + 14 x + 48}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 43, x = 43, x = - 8, x = - 6

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 14 x + 48} : x < - 8 or - 8 < x < - 6 or x > - 6

\frac{x}{x ^{2} + 14 x + 48}

is not defined at

x = - 8, x = - 6

, therefore:

x = - 43, x = 43

cot (x) \cdot arccsc (x)

8 - x

9 - 2 x

5 x - 3 y = 6

f (x) = \frac{9 x}{x ^{2} + 4 x - 5}

What is the critical x/(x^2+14x+48) ?
The critical x/(x^2+14x+48) is x=-4sqrt(3),x=4sqrt(3)