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Popular >

range of f(x)=-(x^2)

Solution

range

f (x) = - (x^{2})

Solution

f (x) \leq 0

+1

Solution steps

Vertex of

- x^{2} :

Maximum

(0, 0)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, 0)

f (x) \leq 0

Popular Examples

domain of (3x+2)/(x+2)domain

\frac{3 x + 2}{x + 2}

inverse of f(x)=sqrt(x^2-10x)inverse

f (x) = x^{2} - 10 x

critical f(x)=3x^2+10x-2 critical points

f (x) = 3 x^{2} + 10 x - 2

domain of x/((x+3))\circ 6/x domain

\frac{x}{( x + 3 )} \circ \frac{6}{x}

inverse of f(x)=((x-3)^7+1)/7 inverse

f (x) = \frac{( x - 3 ) ^{7} + 1}{7}

Frequently Asked Questions (FAQ)

What is the range of f(x)=-(x^2) ?
The range of f(x)=-(x^2) is f(x)<= 0