What is the domain of f(x)= 1/(\frac{4){x-1}-2} ?

The domain of f(x)= 1/(\frac{4){x-1}-2} is x 3

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domain of f(x)= 1/(\frac{4){x-1}-2}

domain

f (x) = \frac{1}{\frac{4}{x - 1} - 2}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 1

The function domain

x < 1 or 1 < x < 3 or x > 3

f (x) = 3 x - 11

f (x) = x^{2} + 9 x - 10

f (x) = 2 x^{2} + 3

2 x + 4

\frac{1}{5} y = x - \frac{1}{5}

What is the domain of f(x)= 1/(\frac{4){x-1}-2} ?
The domain of f(x)= 1/(\frac{4){x-1}-2} is x<1\lor 1<x<3\lor x>3