What is the inverse of f(x)=2x^2+3 ?

The inverse of f(x)=2x^2+3 is sqrt((x-3)/2),-sqrt((x-3)/2)

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inverse of f(x)=2x^2+3

inverse

f (x) = 2 x^{2} + 3

\frac{x - 3}{2}, - \frac{x - 3}{2}

Solution steps

y = 2 x^{2} + 3

Replace

x

with

y

x = 2 y^{2} + 3

Solve for

y, x = 2 y^{2} + 3

\frac{x - 3}{2}, - \frac{x - 3}{2}

2 x + 4

\frac{1}{5} y = x - \frac{1}{5}

f (x) = \frac{x}{x - 1}

f (x) = 2 (x - 3)^{3} + 6

f (x) = 3 - 2 x e n e l (- 1.5)

What is the inverse of f(x)=2x^2+3 ?
The inverse of f(x)=2x^2+3 is sqrt((x-3)/2),-sqrt((x-3)/2)