What is the inverse of f(x)=\sqrt[5]{x+3}+1 ?

The inverse of f(x)=\sqrt[5]{x+3}+1 is x^5-5x^4+10x^3-10x^2+5x-4

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inverse of f(x)=\sqrt[5]{x+3}+1

inverse

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x - 4

Solution steps

Replace

x

with

y

Solve for

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x - 4

(3, 10), (10, 11)

f (x) = \frac{( x - 1 )}{x}

y = 2 x^{2} - 5 x^{8}

f (x) = \frac{1}{2} x - 1

f (x) = \frac{x - 2}{x ^{3} + x}

What is the inverse of f(x)=\sqrt[5]{x+3}+1 ?
The inverse of f(x)=\sqrt[5]{x+3}+1 is x^5-5x^4+10x^3-10x^2+5x-4