What is the inverse of f(x)=((3x-5))/((x+1)) ?

The inverse of f(x)=((3x-5))/((x+1)) is (-5-x)/(x-3)

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inverse of f(x)=((3x-5))/((x+1))

inverse

f (x) = \frac{( 3 x - 5 )}{( x + 1 )}

\frac{- 5 - x}{x - 3}

Solution steps

y = \frac{3 x - 5}{x + 1}

Replace

x

with

y

x = \frac{3 y - 5}{y + 1}

Solve for

y, x = \frac{3 y - 5}{y + 1}

\frac{- 5 - x}{x - 3}

f (x) = \frac{( x + 5 )}{( x ^{2} + 3 x - 10 )}

f (x) = \frac{2 x - 3}{x ^{2} - 5 x + 6}

f (x) = \frac{1}{x + 11}

x - 4

What is the inverse of f(x)=((3x-5))/((x+1)) ?
The inverse of f(x)=((3x-5))/((x+1)) is (-5-x)/(x-3)