What is the shift 0.02sin(0.02x+1.59)+1 ?

The shift 0.02sin(0.02x+1.59)+1 is Phase:-79.5, Vertical:1

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shift 0.02sin(0.02x+1.59)+1

shift

0.02 sin (0.02 x + 1.59) + 1

Phase : - 79.5, Vertical : 1

Solution steps

f (x) = 0.02 sin (0.02 x + 1.59) + 1

g (B x - C) = sin (0.02 x + 1.59), B = 0.02, C = - 1.59, D = 1

Therefore, the phase shift

\frac{C}{B}

\frac{- 1.59}{0.02}

- 79.5

The vertical shift

D

1

1

4 - x^{4}

f (x) = 4 x^{3} - 48 x - 7

f (x) = (x - 2)^{2} (x - 1)

y = \frac{x}{x ^{2} + 4}

0.001 x^{3} + 7 x + 54

What is the shift 0.02sin(0.02x+1.59)+1 ?
The shift 0.02sin(0.02x+1.59)+1 is Phase:-79.5, Vertical:1