What is the shift-1/7 sin(5x+pi/2) ?

The shift-1/7 sin(5x+pi/2) is Phase:-pi/(10), Vertical:0

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shift-1/7 sin(5x+pi/2)

shift

- \frac{1}{7} sin (5 x + \frac{π}{2})

Phase : - \frac{π}{10}, Vertical : 0

Solution steps

f (x) = - \frac{1}{7} sin (5 x + \frac{π}{2})

g (B x - C) = sin (5 x + \frac{π}{2}), B = 5, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{5}

- \frac{π}{10}

The vertical shift

D

0

0

f (x) = \frac{- 7}{- 2 x - 4}

f (x) = \frac{2 x + 1}{1 - 3 x}

f (x) = x^{2} - 5, x \geq 0

f (x) = \frac{x ^{2} + x - 2}{2 x ^{2} - 2}

5 p + 2 q = 4

What is the shift-1/7 sin(5x+pi/2) ?
The shift-1/7 sin(5x+pi/2) is Phase:-pi/(10), Vertical:0