What is the domain of f(x)=arctan(1+e^{-r^2}) ?

The domain of f(x)=arctan(1+e^{-r^2}) is -infinity <r<infinity

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domain of f(x)=arctan(1+e^{-r^2})

domain

f (x) = arctan (1 + e^{- r^{2}})

- \infty < r < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < r < \infty

f (x) = 9 - 3 x^{2}

(0, 16), (7, 10)

f (x) = 3 (5^{x})

- \frac{5}{6}

f (x) = (x - 2)^{3} + 4

What is the domain of f(x)=arctan(1+e^{-r^2}) ?
The domain of f(x)=arctan(1+e^{-r^2}) is -infinity <r<infinity