What is the inverse of f(x)=9-3x^2 ?

The inverse of f(x)=9-3x^2 is sqrt(-(x-9)/3),-sqrt(-(x-9)/3)

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inverse of f(x)=9-3x^2

inverse

f (x) = 9 - 3 x^{2}

- \frac{x - 9}{3}, - - \frac{x - 9}{3}

Solution steps

y = 9 - 3 x^{2}

Replace

x

with

y

x = 9 - 3 y^{2}

Solve for

y, x = 9 - 3 y^{2}

- \frac{x - 9}{3}, - - \frac{x - 9}{3}

(0, 16), (7, 10)

f (x) = 3 (5^{x})

- \frac{5}{6}

f (x) = (x - 2)^{3} + 4

f (x) = (1 + (2 + x)^{\frac{1}{2}})

What is the inverse of f(x)=9-3x^2 ?
The inverse of f(x)=9-3x^2 is sqrt(-(x-9)/3),-sqrt(-(x-9)/3)