What is the inverse of f(x)=(1+(2+x)^{1/2}) ?

The inverse of f(x)=(1+(2+x)^{1/2}) is x^2-2x-1

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inverse of f(x)=(1+(2+x)^{1/2})

inverse

f (x) = (1 + (2 + x)^{\frac{1}{2}})

x^{2} - 2 x - 1

Solution steps

y = 1 + (2 + x)^{\frac{1}{2}}

Replace

x

with

y

x = 1 + (2 + y)^{\frac{1}{2}}

Solve for

y, x = 1 + (2 + y)^{\frac{1}{2}}

x^{2} - 2 x - 1

f (x) = 3 x - 1 + 5

2 X - 3 Y = 6

- 7 sin (2 x + \frac{π}{2})

y = x^{2} + 4 x + 3

\frac{x ^{2} - 9}{x ^{2} + 2 x - 3}

What is the inverse of f(x)=(1+(2+x)^{1/2}) ?
The inverse of f(x)=(1+(2+x)^{1/2}) is x^2-2x-1