What is the domain of f(x)=sqrt(3x-1)+5 ?

The domain of f(x)=sqrt(3x-1)+5 is x>= 1/3

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domain of f(x)=sqrt(3x-1)+5

domain

f (x) = 3 x - 1 + 5

x \geq \frac{1}{3}

Interval Notation

[\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{3}

The function domain

x \geq \frac{1}{3}

2 X - 3 Y = 6

- 7 sin (2 x + \frac{π}{2})

y = x^{2} + 4 x + 3

\frac{x ^{2} - 9}{x ^{2} + 2 x - 3}

f (x) = \frac{2}{5 x + 8}

What is the domain of f(x)=sqrt(3x-1)+5 ?
The domain of f(x)=sqrt(3x-1)+5 is x>= 1/3