What is the inverse of g(x)=(2x-1)/(x+3) ?

The inverse of g(x)=(2x-1)/(x+3) is (-1-3x)/(x-2)

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inverse of g(x)=(2x-1)/(x+3)

inverse

g (x) = \frac{2 x - 1}{x + 3}

\frac{- 1 - 3 x}{x - 2}

Solution steps

y = \frac{2 x - 1}{x + 3}

Replace

x

with

y

x = \frac{2 y - 1}{y + 3}

Solve for

y, x = \frac{2 y - 1}{y + 3}

\frac{- 1 - 3 x}{x - 2}

f (x) = 2 x^{2}

\frac{2}{x} - \frac{x}{x + 2}

f (x) = x 4 - x^{2}

f (x) = \frac{( x + 1 )}{( x - 2 )}

f (x) = 15 - x

What is the inverse of g(x)=(2x-1)/(x+3) ?
The inverse of g(x)=(2x-1)/(x+3) is (-1-3x)/(x-2)