What is the domain of f(x)= x/(x^2+13x+36) ?

The domain of f(x)= x/(x^2+13x+36) is x -4

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domain of f(x)= x/(x^2+13x+36)

domain

f (x) = \frac{x}{x ^{2} + 13 x + 36}

x < - 9 or - 9 < x < - 4 or x > - 4

Interval Notation

(- \infty, - 9) \cup (- 9, - 4) \cup (- 4, \infty)

Solution steps

Find undefined (singularity) points:

x = - 4, x = - 9

The function domain

x < - 9 or - 9 < x < - 4 or x > - 4

f (x) = \frac{1}{5} x - \frac{1}{2}

y = \frac{1}{4} - \frac{3}{2} x

f (x) = {- 4, x > 6}

f (x) = 8 x^{3} - 6 x + 6

What is the domain of f(x)= x/(x^2+13x+36) ?
The domain of f(x)= x/(x^2+13x+36) is x<-9\lor-9<x<-4\lor x>-4