What is the critical 8x^3-24x+12 ?

The critical 8x^3-24x+12 is x=-1,x=1

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critical 8x^3-24x+12

critical points

8 x^{3} - 24 x + 12

x = - 1, x = 1

Solution steps

8 x^{3} - 24 x + 12

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

8 x^{3} - 24 x + 12 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 1

f (x) = \frac{7}{( x - 2 )}

g (x) = 4 x - 3

f (x) = 7 + x

\frac{x}{( x - 8 ) ( x + 8 )}

y = 6^{x}