What is the inverse of f(x)=arccos((2x+1)/(x-3)) ?

The inverse of f(x)=arccos((2x+1)/(x-3)) is (-3cos(x)-1)/(2-cos(x))

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inverse of f(x)=arccos((2x+1)/(x-3))

inverse

f (x) = arccos (\frac{2 x + 1}{x - 3})

\frac{- 3 cos ( x ) - 1}{2 - cos ( x )}

Solution steps

arccos (a) = b \Rightarrow a = cos (b)

\frac{2 x + 1}{x - 3} = cos (y)

Solve for

x, \frac{2 x + 1}{x - 3} = cos (y)

\frac{- 3 cos ( y ) - 1}{2 - cos ( y )}

Substitute

y = x

\frac{- 3 cos ( x ) - 1}{2 - cos ( x )}

(3, - 7), (- 1, 2)

f (x) = (x^{2} - 8 x)

m = - \frac{7}{6}, (- 6, - 2)

f (x) = - x^{4} + x^{3} + 2 x^{2}

f (x) = \frac{x + 1}{2 x + 3}

What is the inverse of f(x)=arccos((2x+1)/(x-3)) ?
The inverse of f(x)=arccos((2x+1)/(x-3)) is (-3cos(x)-1)/(2-cos(x))