What is the monotone (e^{x-3})/(x-2) ?

The monotone (e^{x-3})/(x-2) is Decreasing:-infinity <x<2,Decreasing:2<x<3,Increasing:3<x<infinity

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monotone (e^{x-3})/(x-2)

monotone intervals

\frac{e ^{x - 3}}{x - 2}

Decreasing : - \infty < x < 2, Decreasing : 2 < x < 3, Increasing : 3 < x < \infty

Solution steps

f^{'} (x) = \frac{e ^{x - 3} x - 3 e ^{x - 3}}{( x - 2 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 2,

Decreasing

: 2 < x < 3,

Increasing

: 3 < x < \infty

Decreasing : - \infty < x < 2, Decreasing : 2 < x < 3, Increasing : 3 < x < \infty

9 + (4 + x)^{\frac{1}{2}}

g (x) = - \frac{1}{3} - x - 2 - 4

f (x) = 1 + \frac{9 x - 70}{x ^{2} - 15 x + 56}

ln (x)

(y + 6)^{2} = 4 (x + 5)

What is the monotone (e^{x-3})/(x-2) ?
The monotone (e^{x-3})/(x-2) is Decreasing:-infinity <x<2,Decreasing:2<x<3,Increasing:3<x<infinity