What is the inverse of g(x)=-1/3 sqrt(-x-2)-4 ?

The inverse of g(x)=-1/3 sqrt(-x-2)-4 is -9x^2-72x-146

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inverse of g(x)=-1/3 sqrt(-x-2)-4

inverse

g (x) = - \frac{1}{3} - x - 2 - 4

- 9 x^{2} - 72 x - 146

Solution steps

y = - \frac{1}{3} - x - 2 - 4

Replace

x

with

y

x = - \frac{1}{3} - y - 2 - 4

Solve for

y, x = - \frac{1}{3} - y - 2 - 4

- 9 x^{2} - 72 x - 146

f (x) = 1 + \frac{9 x - 70}{x ^{2} - 15 x + 56}

ln (x)

(y + 6)^{2} = 4 (x + 5)

f (x) = x^{2} - 9 x

- 2 \cdot 3^{x}

What is the inverse of g(x)=-1/3 sqrt(-x-2)-4 ?
The inverse of g(x)=-1/3 sqrt(-x-2)-4 is -9x^2-72x-146