What is the inverse of f(x)=log_{2}(x+1)-5 ?

The inverse of f(x)=log_{2}(x+1)-5 is 2^{x+5}-1

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inverse of f(x)=log_{2}(x+1)-5

inverse

f (x) = lo g_{2} (x + 1) - 5

2^{x + 5} - 1

Solution steps

y = lo g_{2} (x + 1) - 5

Replace

x

with

y

x = lo g_{2} (y + 1) - 5

Solve for

y, x = lo g_{2} (y + 1) - 5

2^{x + 5} - 1

csc (x) + cot (x^{2})

f (x) = x^{2} - x - 56

3 x - 2 y = - 8

\frac{2 x}{x ^{2} - 16}

f (x) = 16 - x^{2} \cdot x + 1

What is the inverse of f(x)=log_{2}(x+1)-5 ?
The inverse of f(x)=log_{2}(x+1)-5 is 2^{x+5}-1