What is the inverse of f(x)=4x^2+8x-20 ?

The inverse of f(x)=4x^2+8x-20 is (-2+sqrt(x+24))/2 ,-(sqrt(x+24)+2)/2

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inverse of f(x)=4x^2+8x-20

inverse

f (x) = 4 x^{2} + 8 x - 20

\frac{- 2 + x + 24}{2}, - \frac{x + 24 + 2}{2}

Solution steps

y = 4 x^{2} + 8 x - 20

Replace

x

with

y

x = 4 y^{2} + 8 y - 20

Solve for

y, x = 4 y^{2} + 8 y - 20

\frac{- 2 + x + 24}{2}, - \frac{x + 24 + 2}{2}

(x + 1)^{2} - 9

x + y = 8

f (x) = x^{2} + 4

lo g_{4} (\frac{x - 3}{x})

lo g_{4} (3^{x})

What is the inverse of f(x)=4x^2+8x-20 ?
The inverse of f(x)=4x^2+8x-20 is (-2+sqrt(x+24))/2 ,-(sqrt(x+24)+2)/2