What is the asymptotes of f(x)=(x+1)/(x^2-9) ?

The asymptotes of f(x)=(x+1)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of f(x)=(x+1)/(x^2-9)

asymptotes

f (x) = \frac{x + 1}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 1}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x + 1}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{x + 1}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

5 (0)

tan (\frac{1}{2} x)

- 4 x + 4 y + 24 = 0

\frac{1}{3 x - 12} 2 x + 6

f (x) = \frac{5}{x + 7} - 8

What is the asymptotes of f(x)=(x+1)/(x^2-9) ?
The asymptotes of f(x)=(x+1)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0