What is the inverse of f(x)=((x-1))/(x-2) ?

The inverse of f(x)=((x-1))/(x-2) is (-1+2x)/(x-1)

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inverse of f(x)=((x-1))/(x-2)

inverse

f (x) = \frac{( x - 1 )}{x - 2}

\frac{- 1 + 2 x}{x - 1}

Solution steps

y = \frac{x - 1}{x - 2}

Replace

x

with

y

x = \frac{y - 1}{y - 2}

Solve for

y, x = \frac{y - 1}{y - 2}

\frac{- 1 + 2 x}{x - 1}

(40, 67), (70, 42)

(3, - 2), (2, - 1)

f (x) = 8 - 5 x

(0.19) (- 3)

f (x) = \frac{x - 3}{( x + 4 ) ^{2}}

What is the inverse of f(x)=((x-1))/(x-2) ?
The inverse of f(x)=((x-1))/(x-2) is (-1+2x)/(x-1)