What is the inverse of y=x-2x^2+1 ?

The inverse of y=x-2x^2+1 is -(-1+sqrt(-8x+9))/4 ,-(-1-sqrt(-8x+9))/4

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inverse of y=x-2x^2+1

inverse

y = x - 2 x^{2} + 1

- \frac{- 1 + - 8 x + 9}{4}, - \frac{- 1 - - 8 x + 9}{4}

Solution steps

y = x - 2 x^{2} + 1

Replace

x

with

y

x = y - 2 y^{2} + 1

Solve for

y, x = y - 2 y^{2} + 1

- \frac{- 1 + - 8 x + 9}{4}, - \frac{- 1 - - 8 x + 9}{4}

f (x) = \frac{1}{x ^{2} - 4 x - 5}

f (x) = \frac{8 + x}{1 - 8 x}

f (x) = 9 - 3 x

\frac{( x + 4 ) ( x + 5 )}{x - 7}

y = \frac{1}{x + 2}

What is the inverse of y=x-2x^2+1 ?
The inverse of y=x-2x^2+1 is -(-1+sqrt(-8x+9))/4 ,-(-1-sqrt(-8x+9))/4