What is the range of log_{10}(1-x^2) ?

The range of log_{10}(1-x^2) is f(x)<= 0

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range of log_{10}(1-x^2)

range

lo g_{10} (1 - x^{2})

f (x) \leq 0

Interval Notation

(- \infty, 0]

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

lo g_{10} (1 - x^{2})

Inverse of

lo g_{10} (1 - x^{2}) : - 1 0^{x} + 1, - - 1 0^{x} + 1

- 1 0^{x} + 1, - - 1 0^{x} + 1

Find the domain of each inverse function

Domain of

- 1 0^{x} + 1 : x \leq 0

Domain of

- - 1 0^{x} + 1 : x \leq 0

Combine the intervals

f (x) \leq 0

f (x) = 0.5 x^{2} - 2 x - 2

f (x) = ln (\frac{( x - 9 )}{x - 3})

x e^{x}

y (θ) = sin (θ + \frac{π}{2})

\frac{9 - x ^{2}}{x + 1}