What is the critical f(x)=36x^3-3x ?

The critical f(x)=36x^3-3x is x=-1/6 ,x= 1/6

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critical f(x)=36x^3-3x

critical points

f (x) = 36 x^{3} - 3 x

x = - \frac{1}{6}, x = \frac{1}{6}

Solution steps

36 x^{3} - 3 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{6}, x = \frac{1}{6}

Identify critical points not in

f (x)

domain

Domain of

36 x^{3} - 3 x : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{6}, x = \frac{1}{6}

y = \frac{1}{2} x + \frac{9}{4}, (- 5, 2)

f (x) = 25 - 7 x

f (x) = 2 x - 4

\frac{( x ^{2} - 5 )}{7 x ^{2}}

7 x - y = - 4

What is the critical f(x)=36x^3-3x ?
The critical f(x)=36x^3-3x is x=-1/6 ,x= 1/6