What is the asymptotes of f(x)=(2x)/(x^2-9) ?

The asymptotes of f(x)=(2x)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of f(x)=(2x)/(x^2-9)

asymptotes

f (x) = \frac{2 x}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{2 x}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{2 x}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

y = \frac{x ^{2} - x}{x ^{2} - 5 x + 4}

y = f (x) = ln (2 x + 1) - 2 x - 1

- x - 2

f (x) = 2 x - 2

What is the asymptotes of f(x)=(2x)/(x^2-9) ?
The asymptotes of f(x)=(2x)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0