What is the domain of y=f(x)=ln(2x+1)-sqrt(2x-1) ?

The domain of y=f(x)=ln(2x+1)-sqrt(2x-1) is x>= 1/2

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domain of y=f(x)=ln(2x+1)-sqrt(2x-1)

domain

y = f (x) = ln (2 x + 1) - 2 x - 1

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find positive values for logs:

x > - \frac{1}{2}

Combine real regions and undefined points for final function domain

x \geq \frac{1}{2}

- x - 2

f (x) = 2 x - 2

f (x) = 4 + 7 25 - x^{2}

f (x) = \frac{x}{x ^{2} + 4 x + 3}

What is the domain of y=f(x)=ln(2x+1)-sqrt(2x-1) ?
The domain of y=f(x)=ln(2x+1)-sqrt(2x-1) is x>= 1/2