What is the extreme f(x)=x-(27x)/(x+3) ?

The extreme f(x)=x-(27x)/(x+3) is Maximum(-12,-48),Minimum(6,-12)

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extreme f(x)=x-(27x)/(x+3)

extreme points

f (x) = x - \frac{27 x}{x + 3}

Maximum (- 12, - 48), Minimum (6, - 12)

Solution steps

f^{'} (x) = 1 - \frac{81}{( x + 3 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 12,

Decreasing

: - 12 < x < - 3,

Decreasing

: - 3 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = - 12

into

x - \frac{27 x}{x + 3} : - 48

Maximum (- 12, - 48)

Plug

x = 6

into

x - \frac{27 x}{x + 3} : - 12

Minimum (6, - 12)

Maximum (- 12, - 48), Minimum (6, - 12)

- 7 x - 2 y = - 8

f (x) = \frac{- 5 x + 5}{3 x + 1}

f (x) = \frac{x ^{2} + 3 x + 2}{x + 2}

f (x) = x^{2} - 6 x + 3

(x - 4) (\frac{x}{2} + 1)^{3}

What is the extreme f(x)=x-(27x)/(x+3) ?
The extreme f(x)=x-(27x)/(x+3) is Maximum(-12,-48),Minimum(6,-12)