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Popular >

midpoint (-4,3),(4,-1)

Solution

midpoint

(- 4, 3), (4, - 1)

Solution

(0, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 4, 3), (x_{2}, y_{2}) = (4, - 1)

= (\frac{4 - 4}{2}, \frac{- 1 + 3}{2})

Refine

= (0, 1)

Popular Examples

range of x^2+6x+8 range

x^{2} + 6 x + 8

domain of f(x)=-3x^2+2 domain

f (x) = - 3 x^{2} + 2

inverse of f(x)=(1-x)^3 inverse

f (x) = (1 - x)^{3}

inverse of f(x)=(1-x)/(4x-3)inverse

f (x) = \frac{1 - x}{4 x - 3}

domain of f(x)=1.8x-2.7 domain

f (x) = 1.8 x - 2.7

Frequently Asked Questions (FAQ)

What is the midpoint (-4,3),(4,-1) ?
The midpoint (-4,3),(4,-1) is (0,1)