What is the critical f(x)=x^2e^x-7 ?

The critical f(x)=x^2e^x-7 is x=-2,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=x^2e^x-7

critical points

f (x) = x^{2} e^{x} - 7

x = - 2, x = 0

Solution steps

x^{2} e^{x} - 7

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} e^{x} - 7 : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0

y = \frac{1}{2} x + 1 (1.4)

y = 3 x + 2

f (x) = \frac{x ^{2} - 2}{3 x}

f (x) = x + sin (x)

(2, - 3), (0, 0)