What is the domain of f(x)=ln(x^2-1) ?

The domain of f(x)=ln(x^2-1) is x 1

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domain of f(x)=ln(x^2-1)

domain

f (x) = ln (x^{2} - 1)

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

f (x) = lo g_{5} (x + 5)

f (x) = (4 \cdot [5 \cdot (x^{2}) - 1] - 8)^{(\frac{1}{2})}

x^{9} - 9 x

f (x) = \frac{( x - 2 ) ^{3}}{64} + 3

f (x) = - \frac{10 x}{x ^{2} + 25}

What is the domain of f(x)=ln(x^2-1) ?
The domain of f(x)=ln(x^2-1) is x<-1\lor x>1