What is the domain of f(x)=(sqrt(x))/(x-1) ?

The domain of f(x)=(sqrt(x))/(x-1) is 0 1

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domain of f(x)=(sqrt(x))/(x-1)

domain

f (x) = \frac{x}{x - 1}

0 \leq x < 1 or x > 1

Interval Notation

[0, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

0 \leq x < 1 or x > 1

cot (3 θ) + 5

f (x) = x^{2} - 5 x + (\frac{4}{x - 2})

f (x) = (x - 4) (x + 1)^{2} (x - 5)

x - x^{2}

f (x) = 4 x^{3} - 18 x^{2} + 24 x

What is the domain of f(x)=(sqrt(x))/(x-1) ?
The domain of f(x)=(sqrt(x))/(x-1) is 0<= x<1\lor x>1