en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

shift cot(3θ)+5

Solution

shift

cot (3 θ) + 5

Solution

Phase : 0, Vertical : 5

Solution steps

f (x) = cot (3 θ) + 5

g (B x - C) = cot (3 θ), B = 3, C = 0, D = 5

Therefore, the phase shift

\frac{C}{B}

is

\frac{0}{3}

0

The vertical shift

D

is

5

5

Popular Examples

domain of f(x)=x^2-5x+(4/(sqrt(x)-2))domain

f (x) = x^{2} - 5 x + (\frac{4}{x - 2})

intercepts of f(x)=(x-4)(x+1)^2(x-5)intercepts

f (x) = (x - 4) (x + 1)^{2} (x - 5)

range of x-x^2 range

x - x^{2}

extreme f(x)=4x^3-18x^2+24x extreme points

f (x) = 4 x^{3} - 18 x^{2} + 24 x

critical f(x)= 1/(x^2+10x+28)critical points

f (x) = \frac{1}{x ^{2} + 10 x + 28}

Frequently Asked Questions (FAQ)

What is the shift cot(3θ)+5 ?
The shift cot(3θ)+5 is Phase:0, Vertical:5