What is the shift f(x)=-3sin(2x+pi/2) ?

The shift f(x)=-3sin(2x+pi/2) is Phase:-pi/4 , Vertical:0

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shift f(x)=-3sin(2x+pi/2)

shift

f (x) = - 3 sin (2 x + \frac{π}{2})

Phase : - \frac{π}{4}, Vertical : 0

Solution steps

f (x) = - 3 sin (2 x + \frac{π}{2})

g (B x - C) = sin (2 x + \frac{π}{2}), B = 2, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{2}

- \frac{π}{4}

The vertical shift

D

0

0

(6, 0), (0, 10)

f (x) = \frac{2}{x ^{2} + 1}

f (x) = 5 - x + 9

\frac{2 x ^{2} - 5 x + 4}{x + 1}

\frac{3 x}{x - 2}

What is the shift f(x)=-3sin(2x+pi/2) ?
The shift f(x)=-3sin(2x+pi/2) is Phase:-pi/4 , Vertical:0