What is the domain of f(x)=sqrt(3-x)+sqrt(x^2-1) ?

The domain of f(x)=sqrt(3-x)+sqrt(x^2-1) is x<=-1\lor 1<= x<= 3

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domain of f(x)=sqrt(3-x)+sqrt(x^2-1)

domain

f (x) = 3 - x + x^{2} - 1

x \leq - 1 or 1 \leq x \leq 3

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq - 1 or 1 \leq x \leq 3

The function domain

x \leq - 1 or 1 \leq x \leq 3

f (x) = x - 9

f (x) = 4 x 2 x^{2} + 2

cos (5 x)

f (x) = \frac{x ^{2} - 4}{2 x ^{2}}

\frac{1}{4} x + 3

What is the domain of f(x)=sqrt(3-x)+sqrt(x^2-1) ?
The domain of f(x)=sqrt(3-x)+sqrt(x^2-1) is x<=-1\lor 1<= x<= 3