What is the domain of f(x)=sqrt(|x^2-1|) ?

The domain of f(x)=sqrt(|x^2-1|) is -infinity <x<infinity

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domain of f(x)=sqrt(|x^2-1|)

domain

f (x) = ∣ x^{2} - 1 ∣

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1}{11.25 x} - \frac{1}{90}

g (x) = 2 x + 4

f (x) = \frac{x + 4}{x - 1}

f (x) = \frac{\frac{x}{x + 1}}{\frac{x}{x + 1} + 1}

(5.2) (5.8)

What is the domain of f(x)=sqrt(|x^2-1|) ?
The domain of f(x)=sqrt(|x^2-1|) is -infinity <x<infinity