What is the domain of f(x)=(x+1)/(sqrt(2x-8)) ?

The domain of f(x)=(x+1)/(sqrt(2x-8)) is x>4

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domain of f(x)=(x+1)/(sqrt(2x-8))

domain

f (x) = \frac{x + 1}{2 x - 8}

x > 4

Interval Notation

(4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

x > 4

x^{3} - x^{2} - x + 2

f (x) = \frac{x ^{3}}{x ^{2} + 3 x - 10}

f (x) = - 2 x - 3

f (x) = \frac{( 12 x - 3 )}{( 9 x ^{2} - 4 )}

(5, 8), (- 3, 4)

What is the domain of f(x)=(x+1)/(sqrt(2x-8)) ?
The domain of f(x)=(x+1)/(sqrt(2x-8)) is x>4