What is the shift f(x)=5sin(2/3 x+2/9 pi) ?

The shift f(x)=5sin(2/3 x+2/9 pi) is Phase:-pi/3 , Vertical:0

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shift f(x)=5sin(2/3 x+2/9 pi)

shift

f (x) = 5 sin (\frac{2}{3} x + \frac{2}{9} π)

Phase : - \frac{π}{3}, Vertical : 0

Solution steps

Simplify

5 sin (\frac{2}{3} x + \frac{2}{9} π) : 5 sin (\frac{2}{3} x + \frac{2 π}{9})

f (x) = 5 sin (\frac{2}{3} x + \frac{2 π}{9})

g (B x - C) = sin (\frac{2}{3} x + \frac{2 π}{9}), B = \frac{2}{3}, C = - \frac{2 π}{9}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{2 π}{9}}{\frac{2}{3}}

- \frac{π}{3}

The vertical shift

D

0

0

f (x) = \frac{x ^{2} + x - 6}{x - 3}

f (x) = x^{4} e^{x} - 4

25 - x^{2}

\frac{ln ( x - 3 )}{ln ( e ^{x} - e ^{3} )}

cos (6 x)

What is the shift f(x)=5sin(2/3 x+2/9 pi) ?
The shift f(x)=5sin(2/3 x+2/9 pi) is Phase:-pi/3 , Vertical:0