What is the critical (x^3)/3+x^2-8x+20 ?

The critical (x^3)/3+x^2-8x+20 is x=-4,x=2

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critical (x^3)/3+x^2-8x+20

critical points

\frac{x ^{3}}{3} + x^{2} - 8 x + 20

x = - 4, x = 2

Solution steps

\frac{x ^{3}}{3} + x^{2} - 8 x + 20

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{3} + x^{2} - 8 x + 20 : - \infty < x < \infty

All critical points are in domain

x = - 4, x = 2

f (x) = 5 sec (3 x - \frac{π}{2})

f (x) = \frac{1}{x - 15}

f (x) = ln (\frac{x}{1 - x ^{2}})

y = - 6

f (x) = - 3 x + 1

What is the critical (x^3)/3+x^2-8x+20 ?
The critical (x^3)/3+x^2-8x+20 is x=-4,x=2