What is the inverse of f(x)=((-x+1))/((1+x)) ?

The inverse of f(x)=((-x+1))/((1+x)) is (1-x)/(x+1)

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inverse of f(x)=((-x+1))/((1+x))

inverse

f (x) = \frac{( - x + 1 )}{( 1 + x )}

\frac{1 - x}{x + 1}

Solution steps

y = \frac{- x + 1}{1 + x}

Replace

x

with

y

x = \frac{- y + 1}{1 + y}

Solve for

y, x = \frac{- y + 1}{1 + y}

\frac{1 - x}{x + 1}

f (x) = \frac{( x + 3 )}{2 x ^{2} - x - 3}

f (x) = - x + 4

f (x) = 16 - x^{4}

f (x) = \frac{3}{2 x - 1}

f (x) = ln (5 x)

What is the inverse of f(x)=((-x+1))/((1+x)) ?
The inverse of f(x)=((-x+1))/((1+x)) is (1-x)/(x+1)