What is the domain of (2x^2-6x+2)/((2x-3)^2) ?

The domain of (2x^2-6x+2)/((2x-3)^2) is x 3/2

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domain of (2x^2-6x+2)/((2x-3)^2)

domain

\frac{2 x ^{2} - 6 x + 2}{( 2 x - 3 ) ^{2}}

x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}

The function domain

x < \frac{3}{2} or x > \frac{3}{2}

(- 2, 4), (4, - 6)

y = \frac{2}{3} x + 1, (3, - 1)

cos (x) - 3

f (x) = \frac{14}{( x - 5 ) ( x + 1 )}

x^{4} - 4 x^{3} + 9

What is the domain of (2x^2-6x+2)/((2x-3)^2) ?
The domain of (2x^2-6x+2)/((2x-3)^2) is x< 3/2 \lor x> 3/2