What is the inflection f(x)=4x^3-6x^2+9x-8 ?

The inflection f(x)=4x^3-6x^2+9x-8 is (1/2 ,-9/2)

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inflection f(x)=4x^3-6x^2+9x-8

inflection points

f (x) = 4 x^{3} - 6 x^{2} + 9 x - 8

(\frac{1}{2}, - \frac{9}{2})

Solution steps

f^{''} (x) = 24 x - 12

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{3} - 6 x^{2} + 9 x - 8 : - \frac{9}{2}

(\frac{1}{2}, - \frac{9}{2})

f (x) = 2 x^{3} + 3

x - 15 y = - 15

\frac{1}{3}

X^{3}

f (x) = \frac{x - 3}{6 x + 1}

What is the inflection f(x)=4x^3-6x^2+9x-8 ?
The inflection f(x)=4x^3-6x^2+9x-8 is (1/2 ,-9/2)