What is the domain of f(x)=(x-3)/(6x+1) ?

The domain of f(x)=(x-3)/(6x+1) is x -1/6

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domain of f(x)=(x-3)/(6x+1)

domain

f (x) = \frac{x - 3}{6 x + 1}

x < - \frac{1}{6} or x > - \frac{1}{6}

Interval Notation

(- \infty, - \frac{1}{6}) \cup (- \frac{1}{6}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{6}

The function domain

x < - \frac{1}{6} or x > - \frac{1}{6}

f (x) = \frac{- 5 x ^{2} - 10 x}{2 x ^{2} - 8}

f (x) = (8 x^{\frac{1}{5}} + 4)^{7}

\frac{x - 2}{x ^{2} - 4}

f (x) = x^{2} + 9

s^{3}

What is the domain of f(x)=(x-3)/(6x+1) ?
The domain of f(x)=(x-3)/(6x+1) is x<-1/6 \lor x>-1/6