en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (2,-6),(4,8)

Solution

midpoint

(2, - 6), (4, 8)

Solution

(3, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (2, - 6), (x_{2}, y_{2}) = (4, 8)

= (\frac{4 + 2}{2}, \frac{8 - 6}{2})

Refine

= (3, 1)

Popular Examples

domain of sqrt(4-x)-sqrt(x^2-9)domain

4 - x - x^{2} - 9

domain of f(x)=log_{2x+3}(x^2+3x-4)domain

f (x) = lo g_{2 x + 3} (x^{2} + 3 x - 4)

asymptotes of y=((x+3)(x-4))/((3x+1)(2x-3))asymptotes

y = \frac{( x + 3 ) ( x - 4 )}{( 3 x + 1 ) ( 2 x - 3 )}

asymptotes of f(x)=(x^3+8)/(x^2+5x+6)asymptotes

f (x) = \frac{x ^{3} + 8}{x ^{2} + 5 x + 6}

domain of f(x)=sin^3(x)domain

f (x) = sin^{3} (x)

Frequently Asked Questions (FAQ)

What is the midpoint (2,-6),(4,8) ?
The midpoint (2,-6),(4,8) is (3,1)