What is the perpendicular y=3x+2,(3,5) ?

The perpendicular y=3x+2,(3,5) is y=-1/3 x+6

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perpendicular y=3x+2,(3,5)

perpendicular

y = 3 x + 2, (3, 5)

y = - \frac{1}{3} x + 6

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x + 2

that passes through

(3, 5)

Find the slope of

y = 3 x + 2 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(3, 5) : y = - \frac{1}{3} x + 6

y = - \frac{1}{3} x + 6

y = x^{2} + 6 x + 7

f (x) = \frac{x + 2}{3 x - 15}

f (x) = \frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2}

3 x + 2 y = 7

What is the perpendicular y=3x+2,(3,5) ?
The perpendicular y=3x+2,(3,5) is y=-1/3 x+6