What is the asymptotes of f(x)=(x^2+1)/(2x^2-3x-2) ?

The asymptotes of f(x)=(x^2+1)/(2x^2-3x-2) is Vertical: x=-1/2 ,x=2,Horizontal: y= 1/2

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asymptotes of f(x)=(x^2+1)/(2x^2-3x-2)

asymptotes

f (x) = \frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2}

Vertical : x = - \frac{1}{2}, x = 2, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2} : x = - \frac{1}{2}, x = 2

Horizontal Asymptotes of

\frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2} :

None

Vertical : x = - \frac{1}{2}, x = 2, Horizontal : y = \frac{1}{2}

3 x + 2 y = 7

f (x) = 4 x^{3} - 48 x - 8

f (x) = 7 x + 6 y = 6

f (x) = \frac{6 + 2 x}{4 - 7 x}

f (x) = \frac{x ^{2} + x - 2}{x ^{2}}

What is the asymptotes of f(x)=(x^2+1)/(2x^2-3x-2) ?
The asymptotes of f(x)=(x^2+1)/(2x^2-3x-2) is Vertical: x=-1/2 ,x=2,Horizontal: y= 1/2