What is the domain of f(x)=sqrt(-5x+40) ?

The domain of f(x)=sqrt(-5x+40) is x<= 8

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domain of f(x)=sqrt(-5x+40)

domain

f (x) = - 5 x + 40

x \leq 8

Interval Notation

(- \infty, 8]

Solution steps

Find non-negative values for radicals:

x \leq 8

The function domain

x \leq 8

f (x) = 2^{\frac{x}{4}}

8 x + 2

2 x - 5

x + 3 y = 5, (2, 5)

1 + x + 2 x^{2} - x^{3}

What is the domain of f(x)=sqrt(-5x+40) ?
The domain of f(x)=sqrt(-5x+40) is x<= 8