What is the inverse of f(x)=\sqrt[3]{5^x}+9 ?

The inverse of f(x)=\sqrt[3]{5^x}+9 is (ln(x^3-27x^2+243x-729))/(ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{5^x}+9

inverse

\frac{ln ( x ^{3} - 27 x ^{2} + 243 x - 729 )}{ln ( 5 )}

Solution steps

Replace

x

with

y

Solve for

\frac{ln ( x ^{3} - 27 x ^{2} + 243 x - 729 )}{ln ( 5 )}

\frac{x + 1}{x ^{2}}

y = x^{\frac{1}{5}}

\frac{1}{8 ( 2 x + 10 ) - 16}

4 - 3 cos (4 x)

y = (x + 10)^{3}

What is the inverse of f(x)=\sqrt[3]{5^x}+9 ?
The inverse of f(x)=\sqrt[3]{5^x}+9 is (ln(x^3-27x^2+243x-729))/(ln(5))