What is the range of f(x)=arccos(((1-2x))/4) ?

The range of f(x)=arccos(((1-2x))/4) is 0<= f(x)<= pi

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range of f(x)=arccos(((1-2x))/4)

range

f (x) = arccos (\frac{( 1 - 2 x )}{4})

0 \leq f (x) \leq π

Interval Notation

[0, π]

Solution steps

The range of the basic

arccos

function is

0 \leq arccos (\frac{1 - 2 x}{4}) \leq π

0 \leq arccos (\frac{1 - 2 x}{4}) \leq π

Therefore the range is

0 \leq f (x) \leq π

f (x) = \frac{( x )}{3 x ^{2} + 2 x - 1}

y = x + 7

2 + x^{2} ln (x)

f (x) = \frac{6 x - 7}{11 x + 8}

g (x) = 1 - x

What is the range of f(x)=arccos(((1-2x))/4) ?
The range of f(x)=arccos(((1-2x))/4) is 0<= f(x)<= pi