What is the range of f(x)=2^{x+1}-1 ?

The range of f(x)=2^{x+1}-1 is f(x)>-1

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range of f(x)=2^{x+1}-1

range

f (x) = 2^{x + 1} - 1

f (x) > - 1

Interval Notation

(- 1, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = - 1

f (x) > - 1

f (x) = \frac{3 x + 1}{1 - 7 x}

x + 4

2 x^{3} + 5

x^{3} - 3 x^{2} - 72 x

f (x) = \frac{( x + 9 )}{x - 5}